Beer’s Law

8 August 2016

The wavelength that my group investigated was 810 nm. The equation for the best-fit line that was drawn for my data came out to be y = 11.211x – 0.0056. The value of Epsilon that corresponded to my data was 11.708. The sixteen points that correlates to my data all seem to rise pretty steadily as the concentration increases expect for the three pre-made solutions which seem to flatten out at an absorbance reading of three. Points one through eleven are on the line of best fit. Points twelve and thirteen are above the line of best fit. Points fourteen through sixteen are below the line of best fit.

The working range for the graph, absorbance vs. concentration, is from .01 M to .1998 M. Using beer’s law calculating an unknown solution that has a % T = 62.5, and epsilon, from the data received, was 11.708 and the path length (b) of 1.00 cm.

Beer’s Law Essay Example

(A = ε b C)A = .204 C = A / ε bConcentration = .204 / (11.708 x 1.00) Concentration = .017 M After the data was collected and plotted from the class results there seem to be a trend in the higher the epsilon was the higher the wavelength was, except for the wavelength of 790 nm. The wavelength that gave the highest epsilon came out to be 810 nm. The wavelength compared to the max wavelength is the exact same number.

In part D, Pathway; the color intensity does change when you view the vials form the two different axes. When you view all the vials on an X axis there does not seem to be any differences between the different amounts of CuSO4 in the fact that they all look like the same shade of blue. But as you look at all the vials form a Y axis point of view you can see the difference between each of the vials. You see that the vial with the least amount of CuSO4, 2 mL, is the lightest shade of blue and the shade of blue darks as the amount of CuSO4 increases to 5 mL. I believe this is because the more mL of CuSO4 in each vial the less amount of light can pass, therefore making the shade of blue darker. I came to the conclusion that the CuSO4 get lighter to darker as the amount of CuSO4 goes from 2 mL to 5 mL.

If pathlenght (b) was .50 cm than the absorbance would decrease by almost half of what it was, .120cm rather than .204 cm. This is because you are cutting the pat length in half. This means that the light has to travel a shorter distance making the absorbance appear lower.

Based on the results from the color wheel worksheet I would expect the green color with a wavelength between 490 – 560 nm to be the maximum absorbance for the res solution. I believe this to be true because red and green are complementary colors and this means that the green is absorbing the wavelength that the red color is giving off.

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